Ok this is just thinking aloud… but

```
d = A sin (alpha); // d is the third side of the triangle formed by A and C, alpha is the angle between A and C
e = B sin (beta); // e is the third side of the triangle formed by B and C, beta is the angle between B and C
c1 = 10 / tan(alpha); // c1 is x coordinate of the intersection point
C - c1 = 10 / tan(beta);
```

so ….

```
C = 10/tan(beta) + 10/tan(alpha);
```

That should be enough to get you started

I know the length of the lines A and B, and that they cross at 10’ but can’t find a way to calculate C. Anyone knows how?