4 replies to this topic

[rego]

Hi there,

wonder if anyone can help :)

here is my code

#include <iostream>
#include <stdlib.h>
#include <stdio.h>
#include <time.h>
#include <list>


using namespace std;
using std::list;

typedef list <int> IntList;

void DisplayList(IntList pipeline)
{
    for (IntList::const_iterator i = pipeline.begin(); i != pipeline.end(); i++ )
    {
        cout << *i << " ";
    }       
}

void PrepList(IntList pipeline)
{
    srand( time(NULL) );
    int num;
    for(int i = 0; i < 3; i++)
    {
        num = rand() % 7;
        pipeline.push_back(num);
    }     
}

   
int main()
{
    IntList pipeline;
  
    PrepList(pipeline); 

    DisplayList(pipeline);// <<<<< NEED THIS TO PRINT THE LIST VALUES
 
    system("PAUSE");
    return 0;
}

I just need some one to point me in the right direction regarding how to change PrepList into a function which can return a <list> type for main() to print out the list (if that's even possible) or any way in which this can be done

To recap i need to be able to create a random list in a function and then display it in the main part of the program using a display function.

At the moment the PrepList function is of type void which is obviously wrong :)

Many Thanks!
Rego

[dave_]

instead of IntList pipeline
type PrepList(IntList &pipeline)
and DisplayList(const IntList &pipeline) look at http://en.wikipedia..../Reference_(C++)




you could alternatively use pointers

[rego]

thank you, i'll try this when i get home :)

[rego]

dave_ said:

instead of IntList pipeline
type PrepList(IntList &pipeline)
and DisplayList(const IntList &pipeline) look at http://en.wikipedia..../Reference_(C++)




you could alternatively use pointers

just tried it and it works like a charm! :) thanks again

[t0rakka]

FYI; _why_ it works is because you did pass by value - a local copy (in the stack) of the list was being modified. >B)