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Probabilities and independence


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#1 dionys

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Posted 16 October 2004 - 11:10 PM

Can you help plz..
i dont know how to prove this:

A,B,C are 3 independent events.
We must prove that A and BUC are independent too
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#2 Ed Mack

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Posted 16 October 2004 - 11:34 PM

hmm, let me sketch this out:

To prove A and BuC are in dependant, BuC must equal BuC|A
(BTW, | is given, so BuC given A must equal BuC)

General: X | Z = (XnZ) / Z

BuC | A = (BuC n A) / A

When A and B dependant , AnB = A|B * B
When A and B independent AnB = A*B

So
BuC | A = (BuC * A) / A
BuC | A = BuC
Therefore, BuC is independant of A

(I hope that's what you're after)





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