2 replies to this topic

[macgadger]

Greetings,

I'm looking for conversion routines from a int value to float.

like im converting a float value to integer to read it in 0-100 like

float avg = 0.220000 /* from 0.000000 to 1.000000 */
int ip = (int)(currentVolume*100);

now ip = 20 , that s exactly what i want... !!

now i want to to convert 20 into 0.220000 , opposite int to float

like a function where i can input a integer value betweek 0 to 100 and it converts to 0.000000 to 1.000000


e.g

float SetMeter( int vValue)
{
// conversation code
}



can anyone here help me out of this....


regards,
thnx in advance!!!

[nomad421]

I don't quite understand. The float to int conversion truncates the remainder, so that your current code evaluates as

int ip = (int)(currentVolume * 100);

currentVolume * 100 is first evaluated as a floating point value, 22.00. Thus, your code should result in ip being assigned the value 22, not 20. To convert an integer back to a floating point value, you can simply cast it. To alter the range, you simply divide. Thus, your function should look something like this:

float SetMeter( int vValue)
{
return static_cast<float>(vValue / 100.0f);
}

I would probably same the function more descriptively to ensure that I didn't forget about the division by 100. Note, that given an integer value of 20, this function will return a floating point value of 0.20; not 0.22. Without any extra information about the original value, it is not possible to recover 0.22 from the integer. Hope this helps.

[macgadger]

nomad421 said:

I don't quite understand. The float to int conversion truncates the remainder, so that your current code evaluates as

int ip = (int)(currentVolume * 100);

currentVolume * 100 is first evaluated as a floating point value, 22.00. Thus, your code should result in ip being assigned the value 22, not 20. To convert an integer back to a floating point value, you can simply cast it. To alter the range, you simply divide. Thus, your function should look something like this:

float SetMeter( int vValue)
{
return static_cast<float>(vValue / 100.0f);
}

I would probably same the function more descriptively to ensure that I didn't forget about the division by 100. Note, that given an integer value of 20, this function will return a floating point value of 0.20; not 0.22. Without any extra information about the original value, it is not possible to recover 0.22 from the integer. Hope this helps.

THNX THIS HELPED ME OUT...............!!! WORKED LIKE CHARM!!!!